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Post by Ron Walker on Sept 6, 2022 11:47:28 GMT -7
Posted by: Ron Walker Apr 1 2008, 07:57 PM QUOTE(charle @ Apr 1 2008, 07:06 PM) * So I actually have 2 jigs ... one for a small drill press (purchased at Harborfreight.com for $29) and one for needles.
The needle rig is very fast but I don't see it as useful for lens setting. I'll describe my drill press jig which may be useful for lenses.
The drill press jig is constructed primarily using a universal joint from my 3/8-inch socket set. Add extension and then a small platform to hold the material to be drilled. The center of the u-joint must be in the exact center of the drill path. The most important thing .... the distance of the exact center of the u-joint to the surface of the material must be exactly the same as the radius of the inscribed sphere of the polyhedron. For a dodecahedron this value is R = 1.114 * E where E is the length of the edge.
I haven't used lenses yet, but here's how I might use this jig. I would attached a "mounting block" of about the right size at the location of the lens. Then use a Forstner bit to create a "land" for the lens that is perpendicular to the gnomic line.
The jig becomes important if the thickness of the material is more that half the diameter of the smallest drill bit. The 38-degree angle in this case would make the dots oval in shape if not corrected. But I am new to all this so I might be all wet.
My other jig could also be adapted for a drill press. The plate swings in just one angle (gnomic angle from the center of the face) and I use a small lazy suzan bearing to rotate the face.
I, for one, would love to see pictures.
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Post by Ron Walker on Sept 6, 2022 11:48:18 GMT -7
Posted by: Ken Miller Apr 2 2008, 06:23 PM QUOTE(charle @ Apr 1 2008, 08:17 AM) * Great. Now I can finally ask my questions re: compared to the original Spitz star maps.
QUOTE 1. Are these even close?I am amazed and impressed. Those are very close! QUOTE 2. I assumed from the pictures of the Spitz A1 the the NCP and SCP are centered on the face of the top and bottom faces. Is this correct?That is correct QUOTE 3. Where is RA=0 located? In the maps I am generating at present, I put RA= 0 at the edge of two faces. It turns out that with this selection, there are no magnitude 3 or brighter stars near the vertical edges on the faces in the Northern hemisphere. But there are several important stars near the edges of the top face.Without checking any further, the accuracy of the charts that I have determined so far suggests that you must have RA=0 in the same place as on the Spitz QUOTE 4. I am currently using a star base of about 3100 stars. Should I have versions with 10,000 stars?The answer to this is definitely not 10,000 stars. You wouldn't be able to have sufficient range in brightness, and still differentiate the constellations. Spitz played tricks with hole sizes to make the constellations "pop out". Much more stars than 1000 would be nice, but it wouldn't be faithful to the original Spitz, and it would give you diminishing returns (in my opinion).
QUOTE Thanks for the help.
Charle'
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Post by Ron Walker on Sept 6, 2022 11:48:42 GMT -7
Posted by: Ken Miller Apr 2 2008, 06:28 PM QUOTE(charle @ Apr 1 2008, 08:26 AM) * Is anyone interested in trying to run the "star generator" program that makes these pictures?
Any takers?
Charle' Charle'
I would definitely be interested. Can I get ahold of the program?
Would it be easy to reduce the number of stars to more closely match the number on the Spitz? That would help me a lot in my mapping project.
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Post by Ron Walker on Sept 6, 2022 11:49:01 GMT -7
Posted by: charle Apr 2 2008, 07:28 PM That's great news for me. I am now working on a version of the program that others can use directly. The program files when compressed require less than 200 Kbytes. This will make the charts available to people with standard telephone access while allowing higher quality output. In addition, I am including the ability to subset the star set based on min to max magnitude.
So thanks to your work I feel comfortable charging ahead but everyone should be aware that I program at a snails pace.
Thanks again Ken.
Charle'
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Post by Ron Walker on Sept 6, 2022 11:56:08 GMT -7
Posted by: Ken Miller Apr 3 2008, 09:43 PM Charle' I had to do this quickly, but I will try to do it better later on. Here is a photo for comparison with your chart for your plate "zero".
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Post by Ron Walker on Sept 6, 2022 12:04:53 GMT -7
Posted by: charle Apr 4 2008, 11:32 AM QUOTE(Ken Miller @ Apr 3 2008, 11:43 PM) * Charle'
I had to do this quickly, but I will try to do it better later on. Here is a photo for comparison with your chart for your plate "zero".
Thanks for the photo. A rough graphical analysis of the image shows about a +2.5 degree shift in right ascension. I would conjecture that Spitz did indeed place RA=0 on the vertical edge and the difference is due to precession.
Thanks Again.
Charle'Posted by: charle Apr 4 2008, 11:32 AM QUOTE(Ken Miller @ Apr 3 2008, 11:43 PM) * Charle'
I had to do this quickly, but I will try to do it better later on. Here is a photo for comparison with your chart for your plate "zero".
Thanks for the photo. A rough graphical analysis of the image shows about a +2.5 degree shift in right ascension. I would conjecture that Spitz did indeed place RA=0 on the vertical edge and the difference is due to precession.
Thanks Again.
Charle'
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Post by Ron Walker on Sept 6, 2022 12:05:24 GMT -7
Posted by: Ken Miller Apr 4 2008, 05:03 PM QUOTE(charle @ Apr 4 2008, 11:32 AM) * Thanks for the photo. A rough graphical analysis of the image shows about a +2.5 degree shift in right ascension. I would conjecture that Spitz did indeed place RA=0 on the vertical edge and the difference is due to precession.
Thanks Again.
Charle' Charle'
I'm looking at this and thinking I see the vertical edge that is in Ursa Major at RA = 12 HR. But as you go around the starball, there probably are other vertical edges that do line up with RA = 0/24. Am I confused? You don't have to answer that, because I undoubtedly am.
I thought precession was about 1 degree every 80 years. If that is the case, a 50 year old starglobe shouldn't be off by 2.5 degrees because of precession. Am I correct?
If anything, I would think that Spitz lined up the edges to minimize the number of bright stars that ended up in inconvenient places. Other than aesthetics, I'm not sure there is a compelling reason why he would precisely line up RA = 0 on a vertical edge.
I am eager to hear you take on all this. This is a good learning experience for me.
Ken
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Post by Ron Walker on Sept 6, 2022 12:06:11 GMT -7
Posted by: charle Apr 4 2008, 10:39 PM QUOTE(Ken Miller @ Apr 4 2008, 07:03 PM) * Charle'
I'm looking at this and thinking I see the vertical edge that is in Ursa Major at RA = 12 HR. But as you go around the starball, there probably are other vertical edges that do line up with RA = 0/24. Am I confused? You don't have to answer that, because I undoubtedly am.
There are 5 vertical edges in the northern hemisphere, on every 72 degrees. Thus there is only one opportunity for a vertical edge to fall exactly on an hour angle. I realize now that I have previously stated the reference incorrectly. My model place RA=0 at the CENTER of one of the faces (not the edge), because this would be the center of a gnomic projection. The center of each face has no distortion, while the edges have significant distortion and the greatest distortion occurs at the vertices. So as you point out, this leaves RA=12 to be close to an edge at about the position of Phad in Ursa Major.
I thought precession was about 1 degree every 80 years. If that is the case, a 50 year old starglobe shouldn't be off by 2.5 degrees because of precession. Am I correct?
Yes. My analysis is rather crude with a number of errors. Since precession has both RA and DEC components, its not accurate to speak of only an RA change although RA is the larger of the two. On the other hand, the closeness of Polaris to the north pole is always a topic of misunderstanding to be dealt with so the DEC component can not be ignored. To get a more accurate value, we need to use a photograph which is as perpendicular as possible to the face using a camera with very little distortion (usually a longer focal length). In spite of the errors in the graphical analysis, it is clear that there is SOME difference. Down the road, I will put proper precession into the program. This will make it easier to get a closer match.
If anything, I would think that Spitz lined up the edges to minimize the number of bright stars that ended up in inconvenient places. Other than aesthetics, I'm not sure there is a compelling reason why he would precisely line up RA = 0 on a vertical edge.
I have a personal interest in how Spitz approached the problem of creating his templates from a computational perspective. He obviously didn't have a PC available. It's possible of course the he got the templates from some one else. But, if he did created them himself (which would require only a knowledge of trigonometry which was fairly common in his time frame) he would have had to make a choice ... I prefer to believe that he was a pretty good architect (as demonstrated by the successful production of a number of machines) so that he would have made a studied choice for the RA=0 assignment. On the other hand, he may have noted as I did that the assignment of RA=0 to the center of a face has the desirable property that there are no major stars on the vertical edges. Also, I would think that such a choice would make it easier to synchronize the star ball with the other projectors.
Does anyone know of a set of star charts which are based on the 12 gnomic projections of a dodecahedron? Usually, star charts chose a pattern so that each band of faces maps evenly to major RA values. For example, the popular 8 chart simple starmap that uses gnomic projections for the poles and 6 projections spanning the equator.
Sorry for the misunderstanding.
Charle'
I am eager to hear you take on all this. This is a good learning experience for me.
Ken
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Post by Ron Walker on Sept 6, 2022 12:06:36 GMT -7
Posted by: charle Apr 6 2008, 10:48 AM After further analysis .... I have added precession to my template generator program and found that you are correct. Although precession since 1950 is non-trivial, it is small compared to the apparent rotation that I see in your photo. So it will have to remain a mystery for now unless someone can shed some light on this.
I will be posting my program shortly.
Charle'
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